Base | Representation |
---|---|
bin | 11110101111111001011… |
… | …010010000100000101011 |
3 | 21111000001112101222211222 |
4 | 132233321122100200223 |
5 | 234104422404234431 |
6 | 4254412133212255 |
7 | 305442304102526 |
oct | 36577132204053 |
9 | 7430045358758 |
10 | 2113013352491 |
11 | 74513aa51258 |
12 | 2a1623a9108b |
13 | 12434413c292 |
14 | 743add53bbd |
15 | 39e6e90557b |
hex | 1ebf969082b |
2113013352491 has 2 divisors, whose sum is σ = 2113013352492. Its totient is φ = 2113013352490.
The previous prime is 2113013352469. The next prime is 2113013352521. The reversal of 2113013352491 is 1942533103112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113013352491 - 210 = 2113013351467 is a prime.
It is not a weakly prime, because it can be changed into another prime (2113013355491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056506676245 + 1056506676246.
It is an arithmetic number, because the mean of its divisors is an integer number (1056506676246).
Almost surely, 22113013352491 is an apocalyptic number.
2113013352491 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113013352491 is an equidigital number, since it uses as much as digits as its factorization.
2113013352491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 2113013352491 in words is "two trillion, one hundred thirteen billion, thirteen million, three hundred fifty-two thousand, four hundred ninety-one".
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