Base | Representation |
---|---|
bin | 11110101111111001011… |
… | …010010000100001001001 |
3 | 21111000001112101222220002 |
4 | 132233321122100201021 |
5 | 234104422404240041 |
6 | 4254412133212345 |
7 | 305442304102601 |
oct | 36577132204111 |
9 | 7430045358802 |
10 | 2113013352521 |
11 | 74513aa51285 |
12 | 2a1623a910b5 |
13 | 12434413c2b6 |
14 | 743add53c01 |
15 | 39e6e90559b |
hex | 1ebf9690849 |
2113013352521 has 2 divisors, whose sum is σ = 2113013352522. Its totient is φ = 2113013352520.
The previous prime is 2113013352491. The next prime is 2113013352523. The reversal of 2113013352521 is 1252533103112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1180264960000 + 932748392521 = 1086400^2 + 965789^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113013352521 - 210 = 2113013351497 is a prime.
Together with 2113013352523, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2113013352523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056506676260 + 1056506676261.
It is an arithmetic number, because the mean of its divisors is an integer number (1056506676261).
Almost surely, 22113013352521 is an apocalyptic number.
It is an amenable number.
2113013352521 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113013352521 is an equidigital number, since it uses as much as digits as its factorization.
2113013352521 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 2113013352521 its reverse (1252533103112), we get a palindrome (3365546455633).
The spelling of 2113013352521 in words is "two trillion, one hundred thirteen billion, thirteen million, three hundred fifty-two thousand, five hundred twenty-one".
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