Base | Representation |
---|---|
bin | 1100010011001010010… |
… | …1001101010010101001 |
3 | 202012102000000101102011 |
4 | 3010302211031102221 |
5 | 11430221303341243 |
6 | 241023143235521 |
7 | 21160155316345 |
oct | 3046245152251 |
9 | 665360011364 |
10 | 211302012073 |
11 | 81681528149 |
12 | 34b50748ba1 |
13 | 16c0599a399 |
14 | a32712a625 |
15 | 576a7bd89d |
hex | 313294d4a9 |
211302012073 has 2 divisors, whose sum is σ = 211302012074. Its totient is φ = 211302012072.
The previous prime is 211302012059. The next prime is 211302012199. The reversal of 211302012073 is 370210203112.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117585210649 + 93716801424 = 342907^2 + 306132^2 .
It is a cyclic number.
It is not a de Polignac number, because 211302012073 - 29 = 211302011561 is a prime.
It is not a weakly prime, because it can be changed into another prime (211302012673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105651006036 + 105651006037.
It is an arithmetic number, because the mean of its divisors is an integer number (105651006037).
Almost surely, 2211302012073 is an apocalyptic number.
It is an amenable number.
211302012073 is a deficient number, since it is larger than the sum of its proper divisors (1).
211302012073 is an equidigital number, since it uses as much as digits as its factorization.
211302012073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 211302012073 its reverse (370210203112), we get a palindrome (581512215185).
The spelling of 211302012073 in words is "two hundred eleven billion, three hundred two million, twelve thousand, seventy-three".
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