Base | Representation |
---|---|
bin | 11110101111111010101… |
… | …010010111011000010111 |
3 | 21111000002222220212222011 |
4 | 132233322222113120113 |
5 | 234104443243232101 |
6 | 4254414203245051 |
7 | 305442650434162 |
oct | 36577252273027 |
9 | 7430088825864 |
10 | 2113034352151 |
11 | 745150894648 |
12 | 2a162ab19787 |
13 | 1243485b2708 |
14 | 743b2a5cad9 |
15 | 39e716a2751 |
hex | 1ebfaa97617 |
2113034352151 has 2 divisors, whose sum is σ = 2113034352152. Its totient is φ = 2113034352150.
The previous prime is 2113034352119. The next prime is 2113034352211. The reversal of 2113034352151 is 1512534303112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113034352151 - 25 = 2113034352119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113034350151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056517176075 + 1056517176076.
It is an arithmetic number, because the mean of its divisors is an integer number (1056517176076).
Almost surely, 22113034352151 is an apocalyptic number.
2113034352151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113034352151 is an equidigital number, since it uses as much as digits as its factorization.
2113034352151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 2113034352151 its reverse (1512534303112), we get a palindrome (3625568655263).
The spelling of 2113034352151 in words is "two trillion, one hundred thirteen billion, thirty-four million, three hundred fifty-two thousand, one hundred fifty-one".
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