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211310012112013 is a prime number
BaseRepresentation
bin110000000010111101110010…
…001101011001110010001101
31000201012001002001202202022101
4300002331302031121302031
5210144100401100041023
62025230251320315101
762336434042132453
oct6002756215316215
91021161061682271
10211310012112013
116136a088aa64a1
121b849367612a91
1390ba5aa87cc69
143a2765dcd49d3
1519669d1da91ad
hexc02f72359c8d

211310012112013 has 2 divisors, whose sum is σ = 211310012112014. Its totient is φ = 211310012112012.

The previous prime is 211310012111983. The next prime is 211310012112029. The reversal of 211310012112013 is 310211210013112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 198367703670249 + 12942308441764 = 14084307^2 + 3597542^2 .

It is a cyclic number.

It is not a de Polignac number, because 211310012112013 - 241 = 209110988856461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211310012119013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655006056006 + 105655006056007.

It is an arithmetic number, because the mean of its divisors is an integer number (105655006056007).

Almost surely, 2211310012112013 is an apocalyptic number.

It is an amenable number.

211310012112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

211310012112013 is an equidigital number, since it uses as much as digits as its factorization.

211310012112013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 211310012112013 its reverse (310211210013112), we get a palindrome (521521222125125).

The spelling of 211310012112013 in words is "two hundred eleven trillion, three hundred ten billion, twelve million, one hundred twelve thousand, thirteen".