Base | Representation |
---|---|
bin | 11110101111111110110… |
… | …101100111111010110111 |
3 | 21111000021212202022111002 |
4 | 132233332311213322313 |
5 | 234110114212143333 |
6 | 4254425145033515 |
7 | 305444461101251 |
oct | 36577665477267 |
9 | 7430255668432 |
10 | 2113104412343 |
11 | 745187396931 |
12 | 2a164a48589b |
13 | 124359c72752 |
14 | 743bc098cd1 |
15 | 39e778e10e8 |
hex | 1ebfed67eb7 |
2113104412343 has 2 divisors, whose sum is σ = 2113104412344. Its totient is φ = 2113104412342.
The previous prime is 2113104412337. The next prime is 2113104412399. The reversal of 2113104412343 is 3432144013112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113104412343 - 222 = 2113100218039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113104442343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056552206171 + 1056552206172.
It is an arithmetic number, because the mean of its divisors is an integer number (1056552206172).
Almost surely, 22113104412343 is an apocalyptic number.
2113104412343 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113104412343 is an equidigital number, since it uses as much as digits as its factorization.
2113104412343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 2113104412343 its reverse (3432144013112), we get a palindrome (5545248425455).
The spelling of 2113104412343 in words is "two trillion, one hundred thirteen billion, one hundred four million, four hundred twelve thousand, three hundred forty-three".
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