Base | Representation |
---|---|
bin | 1100010011001100011… |
… | …1100000100100100101 |
3 | 202012102121221012221022 |
4 | 3010303013200210211 |
5 | 11430231104111231 |
6 | 241024104100525 |
7 | 21160324616612 |
oct | 3046307404445 |
9 | 665377835838 |
10 | 211311003941 |
11 | 81686609944 |
12 | 34b53764745 |
13 | 16c077c810b |
14 | a3283cb509 |
15 | 576b497c7b |
hex | 31331e0925 |
211311003941 has 2 divisors, whose sum is σ = 211311003942. Its totient is φ = 211311003940.
The previous prime is 211311003887. The next prime is 211311003961. The reversal of 211311003941 is 149300113112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 168862643041 + 42448360900 = 410929^2 + 206030^2 .
It is a cyclic number.
It is not a de Polignac number, because 211311003941 - 226 = 211243895077 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211311003941.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211311003961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655501970 + 105655501971.
It is an arithmetic number, because the mean of its divisors is an integer number (105655501971).
Almost surely, 2211311003941 is an apocalyptic number.
It is an amenable number.
211311003941 is a deficient number, since it is larger than the sum of its proper divisors (1).
211311003941 is an equidigital number, since it uses as much as digits as its factorization.
211311003941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 211311003941 in words is "two hundred eleven billion, three hundred eleven million, three thousand, nine hundred forty-one".
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