Base | Representation |
---|---|
bin | 1100010011001100100… |
… | …0010011111010100001 |
3 | 202012102122022220102012 |
4 | 3010303020103322201 |
5 | 11430231132323431 |
6 | 241024112402305 |
7 | 21160326454001 |
oct | 3046310237241 |
9 | 665378286365 |
10 | 211311214241 |
11 | 81686742946 |
12 | 34b53846395 |
13 | 16c0786ca5a |
14 | a328444001 |
15 | 576b4da22b |
hex | 3133213ea1 |
211311214241 has 2 divisors, whose sum is σ = 211311214242. Its totient is φ = 211311214240.
The previous prime is 211311214223. The next prime is 211311214243. The reversal of 211311214241 is 142412113112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 197691390625 + 13619823616 = 444625^2 + 116704^2 .
It is a cyclic number.
It is not a de Polignac number, because 211311214241 - 214 = 211311197857 is a prime.
Together with 211311214243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (211311214243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655607120 + 105655607121.
It is an arithmetic number, because the mean of its divisors is an integer number (105655607121).
Almost surely, 2211311214241 is an apocalyptic number.
It is an amenable number.
211311214241 is a deficient number, since it is larger than the sum of its proper divisors (1).
211311214241 is an equidigital number, since it uses as much as digits as its factorization.
211311214241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 384, while the sum is 23.
Adding to 211311214241 its reverse (142412113112), we get a palindrome (353723327353).
The spelling of 211311214241 in words is "two hundred eleven billion, three hundred eleven million, two hundred fourteen thousand, two hundred forty-one".
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