Base | Representation |
---|---|
bin | 110000000010111111000110… |
… | …111001110010100110001000 |
3 | 1000201012011202002111002000002 |
4 | 300002333012321302212020 |
5 | 210144111303324042440 |
6 | 2025231044315502132 |
7 | 62336514204564506 |
oct | 6002770671624610 |
9 | 1021164662432002 |
10 | 211311433034120 |
11 | 6136a748085291 |
12 | 1b8496a3457948 |
13 | 90ba776075783 |
14 | 3a277568d1676 |
15 | 1966a669d3115 |
hex | c02fc6e72988 |
211311433034120 has 64 divisors (see below), whose sum is σ = 478410844665600. Its totient is φ = 83998568989440.
The previous prime is 211311433034087. The next prime is 211311433034131. The reversal of 211311433034120 is 21430334113112.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24524786 + ... + 32001374.
It is an arithmetic number, because the mean of its divisors is an integer number (7475169447900).
Almost surely, 2211311433034120 is an apocalyptic number.
211311433034120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211311433034120 is an abundant number, since it is smaller than the sum of its proper divisors (267099411631480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211311433034120 is a wasteful number, since it uses less digits than its factorization.
211311433034120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7480998 (or 7480994 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 211311433034120 its reverse (21430334113112), we get a palindrome (232741767147232).
The spelling of 211311433034120 in words is "two hundred eleven trillion, three hundred eleven billion, four hundred thirty-three million, thirty-four thousand, one hundred twenty".
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