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2113121130014 = 21762150621471
BaseRepresentation
bin11110101111111111110…
…101011001011000011110
321111000100001012122211002
4132233333311121120132
5234110133002130024
64254430543230302
7305445053146646
oct36577765313036
97430301178732
102113121130014
11745195875094
122a1653ba8392
13124360576b6b
14743c03ab526
1539e790e46ae
hex1ebffd5961e

2113121130014 has 8 divisors (see below), whose sum is σ = 3356133559488. Its totient is φ = 994409943520.

The previous prime is 2113121130011. The next prime is 2113121130067. The reversal of 2113121130014 is 4100311213112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×21131211300143 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113121130011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31075310702 + ... + 31075310769.

It is an arithmetic number, because the mean of its divisors is an integer number (419516694936).

Almost surely, 22113121130014 is an apocalyptic number.

2113121130014 is a deficient number, since it is larger than the sum of its proper divisors (1243012429474).

2113121130014 is a wasteful number, since it uses less digits than its factorization.

2113121130014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62150621490.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 2113121130014 its reverse (4100311213112), we get a palindrome (6213432343126).

The spelling of 2113121130014 in words is "two trillion, one hundred thirteen billion, one hundred twenty-one million, one hundred thirty thousand, fourteen".

Divisors: 1 2 17 34 62150621471 124301242942 1056560565007 2113121130014