Base | Representation |
---|---|
bin | 1001100111000000010100… |
… | …11100010110100111001011 |
3 | 2202211010212121002010011222 |
4 | 10303200022130112213023 |
5 | 10232204114030114011 |
6 | 112535345425112255 |
7 | 4310460100633121 |
oct | 463401234264713 |
9 | 82733777063158 |
10 | 21131414301131 |
11 | 6807867529472 |
12 | 24534aba8868b |
13 | ba38b746c074 |
14 | 530aa1925911 |
15 | 269a236ccddb |
hex | 13380a7169cb |
21131414301131 has 2 divisors, whose sum is σ = 21131414301132. Its totient is φ = 21131414301130.
The previous prime is 21131414301001. The next prime is 21131414301163. The reversal of 21131414301131 is 13110341413112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21131414301131 is a prime.
It is a super-2 number, since 2×211314143011312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21131414301131.
It is not a weakly prime, because it can be changed into another prime (21131414301181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565707150565 + 10565707150566.
It is an arithmetic number, because the mean of its divisors is an integer number (10565707150566).
Almost surely, 221131414301131 is an apocalyptic number.
21131414301131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21131414301131 is an equidigital number, since it uses as much as digits as its factorization.
21131414301131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 26.
Adding to 21131414301131 its reverse (13110341413112), we get a palindrome (34241755714243).
The spelling of 21131414301131 in words is "twenty-one trillion, one hundred thirty-one billion, four hundred fourteen million, three hundred one thousand, one hundred thirty-one".
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