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21131434453 is a prime number
BaseRepresentation
bin10011101011100010…
…000001100111010101
32000112200112002112111
4103223202001213111
5321234121400303
613412503551021
71345441141423
oct235342014725
960480462474
1021131434453
118a64164518
124118a5b471
131cb9c1348c
141046688113
1583a260b6d
hex4eb8819d5

21131434453 has 2 divisors, whose sum is σ = 21131434454. Its totient is φ = 21131434452.

The previous prime is 21131434433. The next prime is 21131434463. The reversal of 21131434453 is 35443413112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14103462564 + 7027971889 = 118758^2 + 83833^2 .

It is a cyclic number.

It is not a de Polignac number, because 21131434453 - 217 = 21131303381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21131434433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565717226 + 10565717227.

It is an arithmetic number, because the mean of its divisors is an integer number (10565717227).

Almost surely, 221131434453 is an apocalyptic number.

It is an amenable number.

21131434453 is a deficient number, since it is larger than the sum of its proper divisors (1).

21131434453 is an equidigital number, since it uses as much as digits as its factorization.

21131434453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 31.

Adding to 21131434453 its reverse (35443413112), we get a palindrome (56574847565).

The spelling of 21131434453 in words is "twenty-one billion, one hundred thirty-one million, four hundred thirty-four thousand, four hundred fifty-three".