21132113111 has 2 divisors, whose sum is σ = 21132113112. Its totient is φ = 21132113110.

The previous prime is 21132113089. The next prime is 21132113147. The reversal of 21132113111 is 11131123112.

It is a m-pointer prime, because the next prime (21132113147) can be obtained adding 21132113111 to its product of digits (36).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21132113111 - 2³⁰ = 20058371287 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21132113111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21132119111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566056555 + 10566056556.

It is an arithmetic number, because the mean of its divisors is an integer number (10566056556).

Almost surely, 2^21132113111 is an apocalyptic number.

21132113111 is a deficient number, since it is larger than the sum of its proper divisors (1).

21132113111 is an equidigital number, since it uses as much as digits as its factorization.

21132113111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36, while the sum is 17.

Adding to 21132113111 its reverse (11131123112), we get a palindrome (32263236223).

The spelling of 21132113111 in words is "twenty-one billion, one hundred thirty-two million, one hundred thirteen thousand, one hundred eleven".