2113212000040 has 16 divisors (see below), whose sum is σ = 4754727000180. Its totient is φ = 845284800000.

The previous prime is 2113212000017. The next prime is 2113212000061. The reversal of 2113212000040 is 400002123112.

It can be written as a sum of positive squares in 2 ways, for example, as 2096698208004 + 16513792036 = 1447998^2 + 128506^2 .

It is a super-2 number, since 2×2113212000040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113211999978 and 2113212000023.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26415149961 + ... + 26415150040.

Almost surely, 2^{2113212000040} is an apocalyptic number.

2113212000040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2113212000040 is an abundant number, since it is smaller than the sum of its proper divisors (2641515000140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2113212000040 is a wasteful number, since it uses less digits than its factorization.

2113212000040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52830300012 (or 52830300008 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 2113212000040 its reverse (400002123112), we get a palindrome (2513214123152).

The spelling of 2113212000040 in words is "two trillion, one hundred thirteen billion, two hundred twelve million, forty", and thus it is an aban number.