Base | Representation |
---|---|
bin | 11110110000000101011… |
… | …000100101011010111111 |
3 | 21111000120112102011022122 |
4 | 132300011120211122333 |
5 | 234110330321143242 |
6 | 4254444111033155 |
7 | 305450263445642 |
oct | 36600530453277 |
9 | 7430515364278 |
10 | 2113214240447 |
11 | 745233390362 |
12 | 2a167b20b7bb |
13 | 1243769477ab |
14 | 743cc8c7a59 |
15 | 39e82387ad2 |
hex | 1ec056256bf |
2113214240447 has 2 divisors, whose sum is σ = 2113214240448. Its totient is φ = 2113214240446.
The previous prime is 2113214240429. The next prime is 2113214240477. The reversal of 2113214240447 is 7440424123112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113214240447 - 26 = 2113214240383 is a prime.
It is a super-2 number, since 2×21132142404472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113214240477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056607120223 + 1056607120224.
It is an arithmetic number, because the mean of its divisors is an integer number (1056607120224).
Almost surely, 22113214240447 is an apocalyptic number.
2113214240447 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113214240447 is an equidigital number, since it uses as much as digits as its factorization.
2113214240447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 2113214240447 its reverse (7440424123112), we get a palindrome (9553638363559).
The spelling of 2113214240447 in words is "two trillion, one hundred thirteen billion, two hundred fourteen million, two hundred forty thousand, four hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •