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2113223112000 = 26325371113109269
BaseRepresentation
bin11110110000000101111…
…010011011010101000000
321111000121011002212210200
4132300011322123111000
5234110340104041000
64254445025125200
7305450432035350
oct36600572332500
97430534085720
102113223112000
1174523839a720
122a1682189800
13124378732830
14743cdb56b60
1539e8303b500
hex1ec05e9b540

2113223112000 has 2688 divisors, whose sum is σ = 10280811340800. Its totient is φ = 400121856000.

The previous prime is 2113223111971. The next prime is 2113223112019. The reversal of 2113223112000 is 2113223112.

2113223112000 is a `hidden beast` number, since 2 + 11 + 322 + 311 + 20 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 7855847866 + ... + 7855848134.

It is an arithmetic number, because the mean of its divisors is an integer number (3824706600).

Almost surely, 22113223112000 is an apocalyptic number.

2113223112000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2113223112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5140405670400).

2113223112000 is an abundant number, since it is smaller than the sum of its proper divisors (8167588228800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2113223112000 is a wasteful number, since it uses less digits than its factorization.

2113223112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 442 (or 419 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 2113223112000 its reverse (2113223112), we get a palindrome (2115336335112).

2113223112000 divided by its reverse (2113223112) gives a cube (1000 = 103).

It can be divided in two parts, 21132 and 23112000, that added together give a palindrome (23133132).

The spelling of 2113223112000 in words is "two trillion, one hundred thirteen billion, two hundred twenty-three million, one hundred twelve thousand".