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211323433201 is a prime number
BaseRepresentation
bin1100010011001111011…
…0111011000011110001
3202012110111022200200021
43010303312323003301
511430242244330301
6241025230323441
721160535354536
oct3046366730361
9665414280607
10211323433201
1181692629161
1234b57959581
1316c0a25a5ca
14a329d04d8d
15576c6008a1
hex3133dbb0f1

211323433201 has 2 divisors, whose sum is σ = 211323433202. Its totient is φ = 211323433200.

The previous prime is 211323433177. The next prime is 211323433219. The reversal of 211323433201 is 102334323112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121817752576 + 89505680625 = 349024^2 + 299175^2 .

It is a cyclic number.

It is not a de Polignac number, because 211323433201 - 215 = 211323400433 is a prime.

It is not a weakly prime, because it can be changed into another prime (211323433261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105661716600 + 105661716601.

It is an arithmetic number, because the mean of its divisors is an integer number (105661716601).

Almost surely, 2211323433201 is an apocalyptic number.

It is an amenable number.

211323433201 is a deficient number, since it is larger than the sum of its proper divisors (1).

211323433201 is an equidigital number, since it uses as much as digits as its factorization.

211323433201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 211323433201 its reverse (102334323112), we get a palindrome (313657756313).

The spelling of 211323433201 in words is "two hundred eleven billion, three hundred twenty-three million, four hundred thirty-three thousand, two hundred one".