Base | Representation |
---|---|
bin | 110000000011001010111111… |
… | …111111100111110111010011 |
3 | 1000201020101200222120222201010 |
4 | 300003022333333213313103 |
5 | 210144313431204240103 |
6 | 2025240555335342003 |
7 | 62340445504322436 |
oct | 6003127777476723 |
9 | 1021211628528633 |
10 | 211324202024403 |
11 | 613750aa917716 |
12 | 1b850067821903 |
13 | 90bba2c623720 |
14 | 3a282086c581d |
15 | 1967062a02903 |
hex | c032bffe7dd3 |
211324202024403 has 32 divisors (see below), whose sum is σ = 320597799379200. Its totient is φ = 122743157245056.
The previous prime is 211324202024317. The next prime is 211324202024449. The reversal of 211324202024403 is 304420202423112.
It is not a de Polignac number, because 211324202024403 - 28 = 211324202024147 is a prime.
It is a super-2 number, since 2×2113242020244032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (211324202024483) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 529889625 + ... + 530288282.
It is an arithmetic number, because the mean of its divisors is an integer number (10018681230600).
Almost surely, 2211324202024403 is an apocalyptic number.
211324202024403 is a deficient number, since it is larger than the sum of its proper divisors (109273597354797).
211324202024403 is a wasteful number, since it uses less digits than its factorization.
211324202024403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1060178211.
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 211324202024403 its reverse (304420202423112), we get a palindrome (515744404447515).
The spelling of 211324202024403 in words is "two hundred eleven trillion, three hundred twenty-four billion, two hundred two million, twenty-four thousand, four hundred three".
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