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2113243243351 = 11657181285343
BaseRepresentation
bin11110110000000111000…
…111001110001101010111
321111000122112222122211021
4132300013013032031113
5234110410232241401
64254451024422011
7305451065122342
oct36600707161527
97430575878737
102113243243351
1174524879a6a9
122a1688a77907
1312437c960986
14743d26b7459
1539e84bb62a1
hex1ec071ce357

2113243243351 has 4 divisors (see below), whose sum is σ = 2113424540352. Its totient is φ = 2113061946352.

The previous prime is 2113243243313. The next prime is 2113243243429. The reversal of 2113243243351 is 1533423423112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113243243351 - 215 = 2113243210583 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113243243301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90631015 + ... + 90654328.

It is an arithmetic number, because the mean of its divisors is an integer number (528356135088).

Almost surely, 22113243243351 is an apocalyptic number.

2113243243351 is a deficient number, since it is larger than the sum of its proper divisors (181297001).

2113243243351 is a wasteful number, since it uses less digits than its factorization.

2113243243351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181297000.

The product of its digits is 51840, while the sum is 34.

Adding to 2113243243351 its reverse (1533423423112), we get a palindrome (3646666666463).

The spelling of 2113243243351 in words is "two trillion, one hundred thirteen billion, two hundred forty-three million, two hundred forty-three thousand, three hundred fifty-one".

Divisors: 1 11657 181285343 2113243243351