Base | Representation |
---|---|
bin | 11110110000000111000… |
… | …111001110001101010111 |
3 | 21111000122112222122211021 |
4 | 132300013013032031113 |
5 | 234110410232241401 |
6 | 4254451024422011 |
7 | 305451065122342 |
oct | 36600707161527 |
9 | 7430575878737 |
10 | 2113243243351 |
11 | 74524879a6a9 |
12 | 2a1688a77907 |
13 | 12437c960986 |
14 | 743d26b7459 |
15 | 39e84bb62a1 |
hex | 1ec071ce357 |
2113243243351 has 4 divisors (see below), whose sum is σ = 2113424540352. Its totient is φ = 2113061946352.
The previous prime is 2113243243313. The next prime is 2113243243429. The reversal of 2113243243351 is 1533423423112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2113243243351 - 215 = 2113243210583 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113243243301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90631015 + ... + 90654328.
It is an arithmetic number, because the mean of its divisors is an integer number (528356135088).
Almost surely, 22113243243351 is an apocalyptic number.
2113243243351 is a deficient number, since it is larger than the sum of its proper divisors (181297001).
2113243243351 is a wasteful number, since it uses less digits than its factorization.
2113243243351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181297000.
The product of its digits is 51840, while the sum is 34.
Adding to 2113243243351 its reverse (1533423423112), we get a palindrome (3646666666463).
The spelling of 2113243243351 in words is "two trillion, one hundred thirteen billion, two hundred forty-three million, two hundred forty-three thousand, three hundred fifty-one".
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