Base | Representation |
---|---|
bin | 11110110000000111000… |
… | …111001110001100100101 |
3 | 21111000122112222122202102 |
4 | 132300013013032030211 |
5 | 234110410232241201 |
6 | 4254451024421445 |
7 | 305451065122241 |
oct | 36600707161445 |
9 | 7430575878672 |
10 | 2113243243301 |
11 | 74524879a663 |
12 | 2a1688a77885 |
13 | 12437c960948 |
14 | 743d26b7421 |
15 | 39e84bb626b |
hex | 1ec071ce325 |
2113243243301 has 2 divisors, whose sum is σ = 2113243243302. Its totient is φ = 2113243243300.
The previous prime is 2113243243297. The next prime is 2113243243303. The reversal of 2113243243301 is 1033423423112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1867622892100 + 245620351201 = 1366610^2 + 495601^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113243243301 - 22 = 2113243243297 is a prime.
Together with 2113243243303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113243243303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056621621650 + 1056621621651.
It is an arithmetic number, because the mean of its divisors is an integer number (1056621621651).
Almost surely, 22113243243301 is an apocalyptic number.
It is an amenable number.
2113243243301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113243243301 is an equidigital number, since it uses as much as digits as its factorization.
2113243243301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 2113243243301 its reverse (1033423423112), we get a palindrome (3146666666413).
The spelling of 2113243243301 in words is "two trillion, one hundred thirteen billion, two hundred forty-three million, two hundred forty-three thousand, three hundred one".
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