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2113303134101 is a prime number
BaseRepresentation
bin11110110000001010101…
…011101011111110010101
321111000210201200102111012
4132300022223223332111
5234111021100242401
64254501004222005
7305452423153055
oct36601253537625
97430721612435
102113303134101
11745279586495
122a16a4b3a905
1312438c19cca3
14743da627565
1539e8a0968bb
hex1ec0aaebf95

2113303134101 has 2 divisors, whose sum is σ = 2113303134102. Its totient is φ = 2113303134100.

The previous prime is 2113303134091. The next prime is 2113303134113. The reversal of 2113303134101 is 1014313033112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2019283630225 + 94019503876 = 1421015^2 + 306626^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113303134101 is a prime.

It is a super-2 number, since 2×21133031341012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113303134161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056651567050 + 1056651567051.

It is an arithmetic number, because the mean of its divisors is an integer number (1056651567051).

Almost surely, 22113303134101 is an apocalyptic number.

It is an amenable number.

2113303134101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113303134101 is an equidigital number, since it uses as much as digits as its factorization.

2113303134101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 2113303134101 its reverse (1014313033112), we get a palindrome (3127616167213).

The spelling of 2113303134101 in words is "two trillion, one hundred thirteen billion, three hundred three million, one hundred thirty-four thousand, one hundred one".