Base | Representation |
---|---|
bin | 1001100111000011011110… |
… | …00111111101110011001001 |
3 | 2202211022020022112001021102 |
4 | 10303201233013331303021 |
5 | 10232221043441033213 |
6 | 112540225205351145 |
7 | 4310550001334204 |
oct | 463415707756311 |
9 | 82738208461242 |
10 | 21133103455433 |
11 | 6808553a64062 |
12 | 24538a17084b5 |
13 | ba3ac63bbb58 |
14 | 530bc1dc693b |
15 | 269ac1b3d158 |
hex | 13386f1fdcc9 |
21133103455433 has 2 divisors, whose sum is σ = 21133103455434. Its totient is φ = 21133103455432.
The previous prime is 21133103455363. The next prime is 21133103455463. The reversal of 21133103455433 is 33455430133112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17728882882624 + 3404220572809 = 4210568^2 + 1845053^2 .
It is a cyclic number.
It is not a de Polignac number, because 21133103455433 - 212 = 21133103451337 is a prime.
It is not a weakly prime, because it can be changed into another prime (21133103455463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566551727716 + 10566551727717.
It is an arithmetic number, because the mean of its divisors is an integer number (10566551727717).
Almost surely, 221133103455433 is an apocalyptic number.
It is an amenable number.
21133103455433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21133103455433 is an equidigital number, since it uses as much as digits as its factorization.
21133103455433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 21133103455433 its reverse (33455430133112), we get a palindrome (54588533588545).
The spelling of 21133103455433 in words is "twenty-one trillion, one hundred thirty-three billion, one hundred three million, four hundred fifty-five thousand, four hundred thirty-three".
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