211331040000000 has 768 divisors, whose sum is σ = 706673620598400. Its totient is φ = 56162304000000.

The previous prime is 211331039999977. The next prime is 211331040000043. The reversal of 211331040000000 is 40133112.

It is a tau number, because it is divible by the number of its divisors (768).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 190559999446 + ... + 190560000554.

Almost surely, 2^{211331040000000} is an apocalyptic number.

211331040000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211331040000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (353336810299200).

211331040000000 is an abundant number, since it is smaller than the sum of its proper divisors (495342580598400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211331040000000 is an frugal number, since it uses more digits than its factorization.

211331040000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1566 (or 1516 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 211331040000000 its reverse (40133112), we get a palindrome (211331080133112).

The spelling of 211331040000000 in words is "two hundred eleven trillion, three hundred thirty-one billion, forty million", and thus it is an aban number.