Base | Representation |
---|---|
bin | 110000000011010001100011… |
… | …000001000110001110011011 |
3 | 1000201021001211220212000122021 |
4 | 300003101203001012032123 |
5 | 210144422330402030121 |
6 | 2025244121105435311 |
7 | 62341114636555054 |
oct | 6003214301061633 |
9 | 1021231756760567 |
10 | 211331232064411 |
11 | 61378088119838 |
12 | 1b8514aa03bb37 |
13 | 90bc5acc16904 |
14 | 3a286b422172b |
15 | 1967324ca2641 |
hex | c0346304639b |
211331232064411 has 2 divisors, whose sum is σ = 211331232064412. Its totient is φ = 211331232064410.
The previous prime is 211331232064357. The next prime is 211331232064517. The reversal of 211331232064411 is 114460232133112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211331232064411 - 219 = 211331231540123 is a prime.
It is not a weakly prime, because it can be changed into another prime (211331232064111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105665616032205 + 105665616032206.
It is an arithmetic number, because the mean of its divisors is an integer number (105665616032206).
Almost surely, 2211331232064411 is an apocalyptic number.
211331232064411 is a deficient number, since it is larger than the sum of its proper divisors (1).
211331232064411 is an equidigital number, since it uses as much as digits as its factorization.
211331232064411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 34.
Adding to 211331232064411 its reverse (114460232133112), we get a palindrome (325791464197523).
The spelling of 211331232064411 in words is "two hundred eleven trillion, three hundred thirty-one billion, two hundred thirty-two million, sixty-four thousand, four hundred eleven".
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