2113321150051 has 2 divisors, whose sum is σ = 2113321150052. Its totient is φ = 2113321150050.

The previous prime is 2113321150019. The next prime is 2113321150067. The reversal of 2113321150051 is 1500511233112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2113321150051 - 2⁵ = 2113321150019 is a prime.

It is a super-2 number, since 2×2113321150051² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113321149998 and 2113321150025.

It is not a weakly prime, because it can be changed into another prime (2113321150081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056660575025 + 1056660575026.

It is an arithmetic number, because the mean of its divisors is an integer number (1056660575026).

Almost surely, 2^{2113321150051} is an apocalyptic number.

2113321150051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113321150051 is an equidigital number, since it uses as much as digits as its factorization.

2113321150051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 2113321150051 its reverse (1500511233112), we get a palindrome (3613832383163).

The spelling of 2113321150051 in words is "two trillion, one hundred thirteen billion, three hundred twenty-one million, one hundred fifty thousand, fifty-one".