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2113321183843 is a prime number
BaseRepresentation
bin11110110000001011110…
…000100010101001100011
321111000211222122110002011
4132300023300202221203
5234111040210340333
64254502451133351
7305453032450162
oct36601360425143
97430758573064
102113321183843
11745288794531
122a16aaba4257
13124392b4c7cc
14743dcba53d9
1539e8b95e9cd
hex1ec0bc22a63

2113321183843 has 2 divisors, whose sum is σ = 2113321183844. Its totient is φ = 2113321183842.

The previous prime is 2113321183823. The next prime is 2113321183847. The reversal of 2113321183843 is 3483811233112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113321183843 is a prime.

It is a super-2 number, since 2×21133211838432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113321183796 and 2113321183805.

It is not a weakly prime, because it can be changed into another prime (2113321183847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056660591921 + 1056660591922.

It is an arithmetic number, because the mean of its divisors is an integer number (1056660591922).

Almost surely, 22113321183843 is an apocalyptic number.

2113321183843 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113321183843 is an equidigital number, since it uses as much as digits as its factorization.

2113321183843 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 82944, while the sum is 40.

The spelling of 2113321183843 in words is "two trillion, one hundred thirteen billion, three hundred twenty-one million, one hundred eighty-three thousand, eight hundred forty-three".