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211332129947 is a prime number
BaseRepresentation
bin1100010011010001100…
…0000110010010011011
3202012111002200112100222
43010310120012102123
511430302011124242
6241030140550255
721161002315511
oct3046430062233
9665432615328
10211332129947
1181697529154
1234b5a85238b
1316c0bcb3c03
14a32b12a4b1
15576d26c5d2
hex313460649b

211332129947 has 2 divisors, whose sum is σ = 211332129948. Its totient is φ = 211332129946.

The previous prime is 211332129923. The next prime is 211332129949. The reversal of 211332129947 is 749921233112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211332129947 - 28 = 211332129691 is a prime.

It is a super-2 number, since 2×2113321299472 (a number of 23 digits) contains 22 as substring.

Together with 211332129949, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 211332129898 and 211332129907.

It is not a weakly prime, because it can be changed into another prime (211332129949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105666064973 + 105666064974.

It is an arithmetic number, because the mean of its divisors is an integer number (105666064974).

Almost surely, 2211332129947 is an apocalyptic number.

211332129947 is a deficient number, since it is larger than the sum of its proper divisors (1).

211332129947 is an equidigital number, since it uses as much as digits as its factorization.

211332129947 is an evil number, because the sum of its binary digits is even.

The product of its digits is 163296, while the sum is 44.

The spelling of 211332129947 in words is "two hundred eleven billion, three hundred thirty-two million, one hundred twenty-nine thousand, nine hundred forty-seven".