Base | Representation |
---|---|
bin | 11110110000001011111… |
… | …100011110110110010111 |
3 | 21111000212012112110212011 |
4 | 132300023330132312113 |
5 | 234111042011022012 |
6 | 4254503042205051 |
7 | 305453101165054 |
oct | 36601374366627 |
9 | 7430765473764 |
10 | 2113324314007 |
11 | 74528a532245 |
12 | 2a16b0053787 |
13 | 1243936a748a |
14 | 743dd37c02b |
15 | 39e8bd7c1a7 |
hex | 1ec0bf1ed97 |
2113324314007 has 2 divisors, whose sum is σ = 2113324314008. Its totient is φ = 2113324314006.
The previous prime is 2113324313951. The next prime is 2113324314071. The reversal of 2113324314007 is 7004134233112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113324314007 - 239 = 1563568500119 is a prime.
It is a super-2 number, since 2×21133243140072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2113324314007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113324314307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056662157003 + 1056662157004.
It is an arithmetic number, because the mean of its divisors is an integer number (1056662157004).
Almost surely, 22113324314007 is an apocalyptic number.
2113324314007 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113324314007 is an equidigital number, since it uses as much as digits as its factorization.
2113324314007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 2113324314007 its reverse (7004134233112), we get a palindrome (9117458547119).
The spelling of 2113324314007 in words is "two trillion, one hundred thirteen billion, three hundred twenty-four million, three hundred fourteen thousand, seven".
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