Base | Representation |
---|---|
bin | 11110110000001011111… |
… | …100011110110110101111 |
3 | 21111000212012112110220001 |
4 | 132300023330132312233 |
5 | 234111042011022111 |
6 | 4254503042205131 |
7 | 305453101165120 |
oct | 36601374366657 |
9 | 7430765473801 |
10 | 2113324314031 |
11 | 74528a532267 |
12 | 2a16b00537a7 |
13 | 1243936a74a8 |
14 | 743dd37c047 |
15 | 39e8bd7c1c1 |
hex | 1ec0bf1edaf |
2113324314031 has 48 divisors (see below), whose sum is σ = 2599578938880. Its totient is φ = 1682451648000.
The previous prime is 2113324314007. The next prime is 2113324314071. The reversal of 2113324314031 is 1304134233112.
It is not a de Polignac number, because 2113324314031 - 211 = 2113324311983 is a prime.
It is a super-2 number, since 2×21133243140312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113324314071) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 55328166 + ... + 55366348.
It is an arithmetic number, because the mean of its divisors is an integer number (54157894560).
Almost surely, 22113324314031 is an apocalyptic number.
2113324314031 is a deficient number, since it is larger than the sum of its proper divisors (486254624849).
2113324314031 is a wasteful number, since it uses less digits than its factorization.
2113324314031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38584 (or 38567 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 2113324314031 its reverse (1304134233112), we get a palindrome (3417458547143).
The spelling of 2113324314031 in words is "two trillion, one hundred thirteen billion, three hundred twenty-four million, three hundred fourteen thousand, thirty-one".
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