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211332512207 is a prime number
BaseRepresentation
bin1100010011010001100…
…1100011100111001111
3202012111010101221201202
43010310121203213033
511430302110342312
6241030153100115
721161005500125
oct3046431434717
9665433357652
10211332512207
118169776a373
1234b5a9b763b
1316c0c0b8bbb
14a32b1c9915
15576d2e59c2
hex31346639cf

211332512207 has 2 divisors, whose sum is σ = 211332512208. Its totient is φ = 211332512206.

The previous prime is 211332512173. The next prime is 211332512243. The reversal of 211332512207 is 702215233112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211332512207 - 216 = 211332446671 is a prime.

It is a super-2 number, since 2×2113325122072 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211332512207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211332512297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105666256103 + 105666256104.

It is an arithmetic number, because the mean of its divisors is an integer number (105666256104).

Almost surely, 2211332512207 is an apocalyptic number.

211332512207 is a deficient number, since it is larger than the sum of its proper divisors (1).

211332512207 is an equidigital number, since it uses as much as digits as its factorization.

211332512207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 211332512207 its reverse (702215233112), we get a palindrome (913547745319).

The spelling of 211332512207 in words is "two hundred eleven billion, three hundred thirty-two million, five hundred twelve thousand, two hundred seven".