Base | Representation |
---|---|
bin | 11110110000001100011… |
… | …111001001000101100101 |
3 | 21111000212211122002101001 |
4 | 132300030133021011211 |
5 | 234111101322244114 |
6 | 4254504005033301 |
7 | 305453241336424 |
oct | 36601437110545 |
9 | 7430784562331 |
10 | 2113333399909 |
11 | 745294678656 |
12 | 2a16b30b5831 |
13 | 124395538c54 |
14 | 744006652bb |
15 | 39e8ca74374 |
hex | 1ec0c7c9165 |
2113333399909 has 2 divisors, whose sum is σ = 2113333399910. Its totient is φ = 2113333399908.
The previous prime is 2113333399871. The next prime is 2113333399949. The reversal of 2113333399909 is 9099933333112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1843118488225 + 270214911684 = 1357615^2 + 519822^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113333399909 - 227 = 2113199182181 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2113333399909.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113333399949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056666699954 + 1056666699955.
It is an arithmetic number, because the mean of its divisors is an integer number (1056666699955).
Almost surely, 22113333399909 is an apocalyptic number.
It is an amenable number.
2113333399909 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113333399909 is an equidigital number, since it uses as much as digits as its factorization.
2113333399909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3188646, while the sum is 55.
The spelling of 2113333399909 in words is "two trillion, one hundred thirteen billion, three hundred thirty-three million, three hundred ninety-nine thousand, nine hundred nine".
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