Base | Representation |
---|---|
bin | 11110110000001100011… |
… | …111001001000110111111 |
3 | 21111000212211122002111101 |
4 | 132300030133021012333 |
5 | 234111101322244444 |
6 | 4254504005033531 |
7 | 305453241336613 |
oct | 36601437110677 |
9 | 7430784562441 |
10 | 2113333399999 |
11 | 745294678728 |
12 | 2a16b30b58a7 |
13 | 124395538cc3 |
14 | 74400665343 |
15 | 39e8ca743d4 |
hex | 1ec0c7c91bf |
2113333399999 has 4 divisors (see below), whose sum is σ = 2122561930360. Its totient is φ = 2104104869640.
The previous prime is 2113333399981. The next prime is 2113333400011. The reversal of 2113333399999 is 9999933333112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2113333399999 - 27 = 2113333399871 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2113333399999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113333399909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4614264837 + ... + 4614265294.
It is an arithmetic number, because the mean of its divisors is an integer number (530640482590).
Almost surely, 22113333399999 is an apocalyptic number.
2113333399999 is a deficient number, since it is larger than the sum of its proper divisors (9228530361).
2113333399999 is an equidigital number, since it uses as much as digits as its factorization.
2113333399999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9228530360.
The product of its digits is 28697814, while the sum is 64.
The spelling of 2113333399999 in words is "two trillion, one hundred thirteen billion, three hundred thirty-three million, three hundred ninety-nine thousand, nine hundred ninety-nine".
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