Base | Representation |
---|---|
bin | 11110110000001100011… |
… | …111001001001010111001 |
3 | 21111000212211122002211122 |
4 | 132300030133021022321 |
5 | 234111101322301444 |
6 | 4254504005035025 |
7 | 305453241340421 |
oct | 36601437111271 |
9 | 7430784562748 |
10 | 2113333400249 |
11 | 745294678935 |
12 | 2a16b30b5a75 |
13 | 124395539156 |
14 | 74400665481 |
15 | 39e8ca744ee |
hex | 1ec0c7c92b9 |
2113333400249 has 2 divisors, whose sum is σ = 2113333400250. Its totient is φ = 2113333400248.
The previous prime is 2113333400161. The next prime is 2113333400251. The reversal of 2113333400249 is 9420043333112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1240684099600 + 872649300649 = 1113860^2 + 934157^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113333400249 is a prime.
Together with 2113333400251, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2113333403249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056666700124 + 1056666700125.
It is an arithmetic number, because the mean of its divisors is an integer number (1056666700125).
Almost surely, 22113333400249 is an apocalyptic number.
It is an amenable number.
2113333400249 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113333400249 is an equidigital number, since it uses as much as digits as its factorization.
2113333400249 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 35.
The spelling of 2113333400249 in words is "two trillion, one hundred thirteen billion, three hundred thirty-three million, four hundred thousand, two hundred forty-nine".
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