Base | Representation |
---|---|
bin | 1100010011010011011… |
… | …0101000001110111111 |
3 | 202012111122202010220212 |
4 | 3010310312220032333 |
5 | 11430311033231221 |
6 | 241031024303035 |
7 | 21161130331106 |
oct | 3046466501677 |
9 | 665448663825 |
10 | 211340133311 |
11 | 816a0aa51aa |
12 | 34b61471a7b |
13 | 16c10856a28 |
14 | a32c21103d |
15 | 576dcedb5b |
hex | 3134da83bf |
211340133311 has 2 divisors, whose sum is σ = 211340133312. Its totient is φ = 211340133310.
The previous prime is 211340133283. The next prime is 211340133337. The reversal of 211340133311 is 113331043112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211340133311 - 210 = 211340132287 is a prime.
It is a super-2 number, since 2×2113401333112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211340133341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105670066655 + 105670066656.
It is an arithmetic number, because the mean of its divisors is an integer number (105670066656).
Almost surely, 2211340133311 is an apocalyptic number.
211340133311 is a deficient number, since it is larger than the sum of its proper divisors (1).
211340133311 is an equidigital number, since it uses as much as digits as its factorization.
211340133311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 211340133311 its reverse (113331043112), we get a palindrome (324671176423).
The spelling of 211340133311 in words is "two hundred eleven billion, three hundred forty million, one hundred thirty-three thousand, three hundred eleven".
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