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21134031307 is a prime number
BaseRepresentation
bin10011101011101011…
…111011100111001011
32000112212102000202021
4103223223323213023
5321240303000212
613413035345311
71345502205424
oct235353734713
960485360667
1021134031307
118a65678584
1241198b2237
131cba61248c
141046b6264b
1583a5c5307
hex4ebafb9cb

21134031307 has 2 divisors, whose sum is σ = 21134031308. Its totient is φ = 21134031306.

The previous prime is 21134031299. The next prime is 21134031313. The reversal of 21134031307 is 70313043112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21134031307 - 23 = 21134031299 is a prime.

It is a super-2 number, since 2×211340313072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21134031337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10567015653 + 10567015654.

It is an arithmetic number, because the mean of its divisors is an integer number (10567015654).

Almost surely, 221134031307 is an apocalyptic number.

21134031307 is a deficient number, since it is larger than the sum of its proper divisors (1).

21134031307 is an equidigital number, since it uses as much as digits as its factorization.

21134031307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 21134031307 its reverse (70313043112), we get a palindrome (91447074419).

The spelling of 21134031307 in words is "twenty-one billion, one hundred thirty-four million, thirty-one thousand, three hundred seven".