Base | Representation |
---|---|
bin | 10011101011101011… |
… | …111011100111001011 |
3 | 2000112212102000202021 |
4 | 103223223323213023 |
5 | 321240303000212 |
6 | 13413035345311 |
7 | 1345502205424 |
oct | 235353734713 |
9 | 60485360667 |
10 | 21134031307 |
11 | 8a65678584 |
12 | 41198b2237 |
13 | 1cba61248c |
14 | 1046b6264b |
15 | 83a5c5307 |
hex | 4ebafb9cb |
21134031307 has 2 divisors, whose sum is σ = 21134031308. Its totient is φ = 21134031306.
The previous prime is 21134031299. The next prime is 21134031313. The reversal of 21134031307 is 70313043112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21134031307 - 23 = 21134031299 is a prime.
It is a super-2 number, since 2×211340313072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21134031337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10567015653 + 10567015654.
It is an arithmetic number, because the mean of its divisors is an integer number (10567015654).
Almost surely, 221134031307 is an apocalyptic number.
21134031307 is a deficient number, since it is larger than the sum of its proper divisors (1).
21134031307 is an equidigital number, since it uses as much as digits as its factorization.
21134031307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 21134031307 its reverse (70313043112), we get a palindrome (91447074419).
The spelling of 21134031307 in words is "twenty-one billion, one hundred thirty-four million, thirty-one thousand, three hundred seven".
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