Base | Representation |
---|---|
bin | 1100010011010011101… |
… | …1011101111110101111 |
3 | 202012111202010121021111 |
4 | 3010310323131332233 |
5 | 11430311344331111 |
6 | 241031111412451 |
7 | 21161144164024 |
oct | 3046473357657 |
9 | 665452117244 |
10 | 211341402031 |
11 | 816a1791431 |
12 | 34b61984127 |
13 | 16c10bac356 |
14 | a32c46154b |
15 | 576de9ea21 |
hex | 3134eddfaf |
211341402031 has 2 divisors, whose sum is σ = 211341402032. Its totient is φ = 211341402030.
The previous prime is 211341402023. The next prime is 211341402047. The reversal of 211341402031 is 130204143112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211341402031 - 23 = 211341402023 is a prime.
It is a super-2 number, since 2×2113414020312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211341401993 and 211341402011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211341402001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105670701015 + 105670701016.
It is an arithmetic number, because the mean of its divisors is an integer number (105670701016).
Almost surely, 2211341402031 is an apocalyptic number.
211341402031 is a deficient number, since it is larger than the sum of its proper divisors (1).
211341402031 is an equidigital number, since it uses as much as digits as its factorization.
211341402031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 211341402031 its reverse (130204143112), we get a palindrome (341545545143).
The spelling of 211341402031 in words is "two hundred eleven billion, three hundred forty-one million, four hundred two thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •