Base | Representation |
---|---|
bin | 11110110000010001101… |
… | …001100101000101010111 |
3 | 21111001002212121221200110 |
4 | 132300101221211011113 |
5 | 234111241011201403 |
6 | 4254520341414103 |
7 | 305455342533315 |
oct | 36602151450527 |
9 | 7431085557613 |
10 | 2113420022103 |
11 | 745329562145 |
12 | 2a171810a333 |
13 | 1243aa4775a0 |
14 | 7440bd730b5 |
15 | 39e95485103 |
hex | 1ec11a65157 |
2113420022103 has 64 divisors (see below), whose sum is σ = 3125473247232. Its totient is φ = 1262134487040.
The previous prime is 2113420022101. The next prime is 2113420022107. The reversal of 2113420022103 is 3012200243112.
It is not a de Polignac number, because 2113420022103 - 21 = 2113420022101 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2113420022103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113420022101) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 239313898 + ... + 239322728.
It is an arithmetic number, because the mean of its divisors is an integer number (48835519488).
Almost surely, 22113420022103 is an apocalyptic number.
2113420022103 is a deficient number, since it is larger than the sum of its proper divisors (1012053225129).
2113420022103 is a wasteful number, since it uses less digits than its factorization.
2113420022103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9984.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 2113420022103 its reverse (3012200243112), we get a palindrome (5125620265215).
The spelling of 2113420022103 in words is "two trillion, one hundred thirteen billion, four hundred twenty million, twenty-two thousand, one hundred three".
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