Base | Representation |
---|---|
bin | 11110110000010001111… |
… | …001100110000100001111 |
3 | 21111001010011112020201002 |
4 | 132300101321212010033 |
5 | 234111243100023211 |
6 | 4254521011410515 |
7 | 305455423320326 |
oct | 36602171460417 |
9 | 7431104466632 |
10 | 2113424220431 |
11 | 74533096a437 |
12 | 2a17195b3a3b |
13 | 1243ab2b74c4 |
14 | 7440c7470bd |
15 | 39e95a1403b |
hex | 1ec11e6610f |
2113424220431 has 2 divisors, whose sum is σ = 2113424220432. Its totient is φ = 2113424220430.
The previous prime is 2113424220407. The next prime is 2113424220437. The reversal of 2113424220431 is 1340224243112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113424220431 - 26 = 2113424220367 is a prime.
It is a super-2 number, since 2×21134242204312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2113424220394 and 2113424220403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113424220437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056712110215 + 1056712110216.
It is an arithmetic number, because the mean of its divisors is an integer number (1056712110216).
Almost surely, 22113424220431 is an apocalyptic number.
2113424220431 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113424220431 is an equidigital number, since it uses as much as digits as its factorization.
2113424220431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 2113424220431 its reverse (1340224243112), we get a palindrome (3453648463543).
The spelling of 2113424220431 in words is "two trillion, one hundred thirteen billion, four hundred twenty-four million, two hundred twenty thousand, four hundred thirty-one".
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