Base | Representation |
---|---|
bin | 110000000011011011111110… |
… | …100110010001010000110011 |
3 | 1000201022010202110220110210001 |
4 | 300003123332212101100303 |
5 | 210200113300121241034 |
6 | 2025253212323450431 |
7 | 62341662326341453 |
oct | 6003337646212063 |
9 | 1021263673813701 |
10 | 211342432212019 |
11 | 61381905330479 |
12 | 1b8536b4b26a17 |
13 | 90c067644a7a4 |
14 | 3a29057911d63 |
15 | 196777d1c9a14 |
hex | c036fe991433 |
211342432212019 has 2 divisors, whose sum is σ = 211342432212020. Its totient is φ = 211342432212018.
The previous prime is 211342432211993. The next prime is 211342432212071. The reversal of 211342432212019 is 910212234243112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211342432212019 - 235 = 211308072473651 is a prime.
It is a super-2 number, since 2×2113424322120192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211342432212419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105671216106009 + 105671216106010.
It is an arithmetic number, because the mean of its divisors is an integer number (105671216106010).
Almost surely, 2211342432212019 is an apocalyptic number.
211342432212019 is a deficient number, since it is larger than the sum of its proper divisors (1).
211342432212019 is an equidigital number, since it uses as much as digits as its factorization.
211342432212019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 211342432212019 in words is "two hundred eleven trillion, three hundred forty-two billion, four hundred thirty-two million, two hundred twelve thousand, nineteen".
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