Base | Representation |
---|---|
bin | 110000000011011011111110… |
… | …100110010001010000011001 |
3 | 1000201022010202110220110202002 |
4 | 300003123332212101100121 |
5 | 210200113300121240433 |
6 | 2025253212323450345 |
7 | 62341662326341415 |
oct | 6003337646212031 |
9 | 1021263673813662 |
10 | 211342432211993 |
11 | 61381905330455 |
12 | 1b8536b4b269b5 |
13 | 90c067644a784 |
14 | 3a29057911d45 |
15 | 196777d1c99e8 |
hex | c036fe991419 |
211342432211993 has 2 divisors, whose sum is σ = 211342432211994. Its totient is φ = 211342432211992.
The previous prime is 211342432211861. The next prime is 211342432212019. The reversal of 211342432211993 is 399112234243112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114504295646224 + 96838136565769 = 10700668^2 + 9840637^2 .
It is a cyclic number.
It is not a de Polignac number, because 211342432211993 - 218 = 211342431949849 is a prime.
It is not a weakly prime, because it can be changed into another prime (211342432211593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105671216105996 + 105671216105997.
It is an arithmetic number, because the mean of its divisors is an integer number (105671216105997).
Almost surely, 2211342432211993 is an apocalyptic number.
It is an amenable number.
211342432211993 is a deficient number, since it is larger than the sum of its proper divisors (1).
211342432211993 is an equidigital number, since it uses as much as digits as its factorization.
211342432211993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 559872, while the sum is 47.
The spelling of 211342432211993 in words is "two hundred eleven trillion, three hundred forty-two billion, four hundred thirty-two million, two hundred eleven thousand, nine hundred ninety-three".
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