Base | Representation |
---|---|
bin | 11110110000010010010… |
… | …011111000110100110010 |
3 | 21111001010122111102112210 |
4 | 132300102103320310302 |
5 | 234111301331104020 |
6 | 4254521415232550 |
7 | 305455536025320 |
oct | 36602223706462 |
9 | 7431118442483 |
10 | 2113431113010 |
11 | 745334847988 |
12 | 2a171b978756 |
13 | 1243ac85b859 |
14 | 7440d61cd10 |
15 | 39e964263e0 |
hex | 1ec124f8d32 |
2113431113010 has 128 divisors (see below), whose sum is σ = 5854521913344. Its totient is φ = 478265368320.
The previous prime is 2113431112993. The next prime is 2113431113023. The reversal of 2113431113010 is 103111343112.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 117593325 + ... + 117611295.
It is an arithmetic number, because the mean of its divisors is an integer number (45738452448).
Almost surely, 22113431113010 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2113431113010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2927260956672).
2113431113010 is an abundant number, since it is smaller than the sum of its proper divisors (3741090800334).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2113431113010 is a wasteful number, since it uses less digits than its factorization.
2113431113010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23528.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 2113431113010 its reverse (103111343112), we get a palindrome (2216542456122).
The spelling of 2113431113010 in words is "two trillion, one hundred thirteen billion, four hundred thirty-one million, one hundred thirteen thousand, ten".
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