Base | Representation |
---|---|
bin | 1001100111000101101111… |
… | …01110000100010111010011 |
3 | 2202211102101012022012201102 |
4 | 10303202313232010113103 |
5 | 10232231042234401342 |
6 | 112540550114255015 |
7 | 4310622120613565 |
oct | 463426756042723 |
9 | 82742335265642 |
10 | 21134321403347 |
11 | 6809019509389 |
12 | 2453b8158746b |
13 | ba3c5b8286a9 |
14 | 530c99a69335 |
15 | 269b43a21832 |
hex | 1338b7b845d3 |
21134321403347 has 2 divisors, whose sum is σ = 21134321403348. Its totient is φ = 21134321403346.
The previous prime is 21134321403319. The next prime is 21134321403451. The reversal of 21134321403347 is 74330412343112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21134321403347 - 222 = 21134317209043 is a prime.
It is a super-2 number, since 2×211343214033472 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21134321403347.
It is not a weakly prime, because it can be changed into another prime (21134321402347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10567160701673 + 10567160701674.
It is an arithmetic number, because the mean of its divisors is an integer number (10567160701674).
Almost surely, 221134321403347 is an apocalyptic number.
21134321403347 is a deficient number, since it is larger than the sum of its proper divisors (1).
21134321403347 is an equidigital number, since it uses as much as digits as its factorization.
21134321403347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 21134321403347 its reverse (74330412343112), we get a palindrome (95464733746459).
The spelling of 21134321403347 in words is "twenty-one trillion, one hundred thirty-four billion, three hundred twenty-one million, four hundred three thousand, three hundred forty-seven".
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