Base | Representation |
---|---|
bin | 1001100111000101101111… |
… | …01110000100011101100111 |
3 | 2202211102101012022020021101 |
4 | 10303202313232010131213 |
5 | 10232231042234410001 |
6 | 112540550114300531 |
7 | 4310622120615013 |
oct | 463426756043547 |
9 | 82742335266241 |
10 | 21134321403751 |
11 | 6809019509716 |
12 | 2453b81587747 |
13 | ba3c5b82892a |
14 | 530c99a69543 |
15 | 269b43a21a01 |
hex | 1338b7b84767 |
21134321403751 has 2 divisors, whose sum is σ = 21134321403752. Its totient is φ = 21134321403750.
The previous prime is 21134321403703. The next prime is 21134321403787. The reversal of 21134321403751 is 15730412343112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21134321403751 - 27 = 21134321403623 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21134321403751.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21134321403451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10567160701875 + 10567160701876.
It is an arithmetic number, because the mean of its divisors is an integer number (10567160701876).
Almost surely, 221134321403751 is an apocalyptic number.
21134321403751 is a deficient number, since it is larger than the sum of its proper divisors (1).
21134321403751 is an equidigital number, since it uses as much as digits as its factorization.
21134321403751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 21134321403751 its reverse (15730412343112), we get a palindrome (36864733746863).
The spelling of 21134321403751 in words is "twenty-one trillion, one hundred thirty-four billion, three hundred twenty-one million, four hundred three thousand, seven hundred fifty-one".
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