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2113433134 = 21056716567
BaseRepresentation
bin111110111111000…
…0110111000101110
312110021210112020021
41331332012320232
513312014330014
6545414112354
7103241612431
oct17576067056
95407715207
102113433134
11994a8365a
124ab94b6ba
13278b12267
14160985818
15c581c624
hex7df86e2e

2113433134 has 4 divisors (see below), whose sum is σ = 3170149704. Its totient is φ = 1056716566.

The previous prime is 2113433123. The next prime is 2113433143. The reversal of 2113433134 is 4313343112.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×21134331342 = 8933199223778123912, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113433099 and 2113433108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528358282 + ... + 528358285.

It is an arithmetic number, because the mean of its divisors is an integer number (792537426).

Almost surely, 22113433134 is an apocalyptic number.

2113433134 is a deficient number, since it is larger than the sum of its proper divisors (1056716570).

2113433134 is a wasteful number, since it uses less digits than its factorization.

2113433134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1056716569.

The product of its digits is 2592, while the sum is 25.

The square root of 2113433134 is about 45972.0908160593. The cubic root of 2113433134 is about 1283.3038700756.

Adding to 2113433134 its reverse (4313343112), we get a palindrome (6426776246).

The spelling of 2113433134 in words is "two billion, one hundred thirteen million, four hundred thirty-three thousand, one hundred thirty-four".

Divisors: 1 2 1056716567 2113433134