Base | Representation |
---|---|
bin | 1100010011010100001… |
… | …1001000010101101100 |
3 | 202012111212220122102201 |
4 | 3010311003020111230 |
5 | 11430312403114130 |
6 | 241031222431244 |
7 | 21161200230523 |
oct | 3046503102554 |
9 | 665455818381 |
10 | 211343410540 |
11 | 816a2933459 |
12 | 34b62592524 |
13 | 16c11433612 |
14 | a32c8254ba |
15 | 576e249bca |
hex | 31350c856c |
211343410540 has 24 divisors (see below), whose sum is σ = 445100200272. Its totient is φ = 84293737920.
The previous prime is 211343410517. The next prime is 211343410541. The reversal of 211343410540 is 45014343112.
It is a junction number, because it is equal to n+sod(n) for n = 211343410499 and 211343410508.
It is not an unprimeable number, because it can be changed into a prime (211343410541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15219531 + ... + 15233410.
It is an arithmetic number, because the mean of its divisors is an integer number (18545841678).
Almost surely, 2211343410540 is an apocalyptic number.
211343410540 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211343410540 is an abundant number, since it is smaller than the sum of its proper divisors (233756789732).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211343410540 is a wasteful number, since it uses less digits than its factorization.
211343410540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30453297 (or 30453295 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 211343410540 its reverse (45014343112), we get a palindrome (256357753652).
The spelling of 211343410540 in words is "two hundred eleven billion, three hundred forty-three million, four hundred ten thousand, five hundred forty".
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