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2113634251049 is a prime number
BaseRepresentation
bin11110110000011110011…
…010110011000100101001
321111001122210201220112212
4132300132122303010221
5234112210332013144
64254553513214505
7305463553462436
oct36603632630451
97431583656485
102113634251049
11745429483562
122a1777a01435
13124412974289
147442c5bab8d
1539ea91a049e
hex1ec1e6b3129

2113634251049 has 2 divisors, whose sum is σ = 2113634251050. Its totient is φ = 2113634251048.

The previous prime is 2113634251009. The next prime is 2113634251063. The reversal of 2113634251049 is 9401524363112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2107630325824 + 6003925225 = 1451768^2 + 77485^2 .

It is a cyclic number.

It is not a de Polignac number, because 2113634251049 - 236 = 2044914774313 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2113634250997 and 2113634251015.

It is not a weakly prime, because it can be changed into another prime (2113634251009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056817125524 + 1056817125525.

It is an arithmetic number, because the mean of its divisors is an integer number (1056817125525).

Almost surely, 22113634251049 is an apocalyptic number.

It is an amenable number.

2113634251049 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113634251049 is an equidigital number, since it uses as much as digits as its factorization.

2113634251049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 2113634251049 in words is "two trillion, one hundred thirteen billion, six hundred thirty-four million, two hundred fifty-one thousand, forty-nine".