Base | Representation |
---|---|
bin | 11110110000011111011… |
… | …100010001000001110111 |
3 | 21111001201000000211110210 |
4 | 132300133130101001313 |
5 | 234112224230204421 |
6 | 4254555325120503 |
7 | 305464152401550 |
oct | 36603734210167 |
9 | 7431630024423 |
10 | 2113651413111 |
11 | 745438135687 |
12 | 2a17816b9133 |
13 | 1244163a2a44 |
14 | 744309a7327 |
15 | 39eaa940576 |
hex | 1ec1f711077 |
2113651413111 has 32 divisors (see below), whose sum is σ = 3223993909248. Its totient is φ = 1206604424160.
The previous prime is 2113651413103. The next prime is 2113651413113. The reversal of 2113651413111 is 1113141563112.
It is not a de Polignac number, because 2113651413111 - 23 = 2113651413103 is a prime.
It is a super-2 number, since 2×21136514131112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113651413113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 131577066 + ... + 131593128.
It is an arithmetic number, because the mean of its divisors is an integer number (100749809664).
Almost surely, 22113651413111 is an apocalyptic number.
2113651413111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2113651413111 is a deficient number, since it is larger than the sum of its proper divisors (1110342496137).
2113651413111 is a wasteful number, since it uses less digits than its factorization.
2113651413111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21891.
The product of its digits is 2160, while the sum is 30.
Adding to 2113651413111 its reverse (1113141563112), we get a palindrome (3226792976223).
The spelling of 2113651413111 in words is "two trillion, one hundred thirteen billion, six hundred fifty-one million, four hundred thirteen thousand, one hundred eleven".
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