Base | Representation |
---|---|
bin | 10011101100000011… |
… | …111001100101001001 |
3 | 2000120022020020120221 |
4 | 103230003321211021 |
5 | 321243410030231 |
6 | 13413422150041 |
7 | 1345606464541 |
oct | 235403714511 |
9 | 60508206527 |
10 | 21140314441 |
11 | 8a6917a154 |
12 | 411ba22321 |
13 | 1cbba022cc |
14 | 104791a321 |
15 | 83ae16d11 |
hex | 4ec0f9949 |
21140314441 has 2 divisors, whose sum is σ = 21140314442. Its totient is φ = 21140314440.
The previous prime is 21140314373. The next prime is 21140314511. The reversal of 21140314441 is 14441304112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14562455625 + 6577858816 = 120675^2 + 81104^2 .
It is a cyclic number.
It is not a de Polignac number, because 21140314441 - 225 = 21106760009 is a prime.
It is not a weakly prime, because it can be changed into another prime (21140314541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570157220 + 10570157221.
It is an arithmetic number, because the mean of its divisors is an integer number (10570157221).
Almost surely, 221140314441 is an apocalyptic number.
It is an amenable number.
21140314441 is a deficient number, since it is larger than the sum of its proper divisors (1).
21140314441 is an equidigital number, since it uses as much as digits as its factorization.
21140314441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 21140314441 its reverse (14441304112), we get a palindrome (35581618553).
The spelling of 21140314441 in words is "twenty-one billion, one hundred forty million, three hundred fourteen thousand, four hundred forty-one".
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