Base | Representation |
---|---|
bin | 11110110000110110100… |
… | …111011000001111110111 |
3 | 21111002201002121100212211 |
4 | 132300312213120033313 |
5 | 234114023242432411 |
6 | 4255102054154251 |
7 | 305506613141536 |
oct | 36606647301767 |
9 | 7432632540784 |
10 | 2114040202231 |
11 | 745617643701 |
12 | 2a186b952987 |
13 | 124478aba589 |
14 | 7446a49031d |
15 | 39eceb3c221 |
hex | 1ec369d83f7 |
2114040202231 has 2 divisors, whose sum is σ = 2114040202232. Its totient is φ = 2114040202230.
The previous prime is 2114040202151. The next prime is 2114040202279. The reversal of 2114040202231 is 1322020404112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2114040202231 - 27 = 2114040202103 is a prime.
It is a super-2 number, since 2×21140402022312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2114040206231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057020101115 + 1057020101116.
It is an arithmetic number, because the mean of its divisors is an integer number (1057020101116).
Almost surely, 22114040202231 is an apocalyptic number.
2114040202231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114040202231 is an equidigital number, since it uses as much as digits as its factorization.
2114040202231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 2114040202231 its reverse (1322020404112), we get a palindrome (3436060606343).
The spelling of 2114040202231 in words is "two trillion, one hundred fourteen billion, forty million, two hundred two thousand, two hundred thirty-one".
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