Base | Representation |
---|---|
bin | 11110110000110110101… |
… | …111011011011011010111 |
3 | 21111002201020120120111111 |
4 | 132300312233123123113 |
5 | 234114024312444112 |
6 | 4255102211315451 |
7 | 305506640110624 |
oct | 36606657333327 |
9 | 7432636516444 |
10 | 2114042312407 |
11 | 745618855053 |
12 | 2a18705abb87 |
13 | 124479378bbc |
14 | 7446a87d34b |
15 | 39ecee075a7 |
hex | 1ec36bdb6d7 |
2114042312407 has 2 divisors, whose sum is σ = 2114042312408. Its totient is φ = 2114042312406.
The previous prime is 2114042312383. The next prime is 2114042312413. The reversal of 2114042312407 is 7042132404112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2114042312407 - 239 = 1564286498519 is a prime.
It is a super-2 number, since 2×21140423124072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2114042312467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057021156203 + 1057021156204.
It is an arithmetic number, because the mean of its divisors is an integer number (1057021156204).
Almost surely, 22114042312407 is an apocalyptic number.
2114042312407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114042312407 is an equidigital number, since it uses as much as digits as its factorization.
2114042312407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 2114042312407 its reverse (7042132404112), we get a palindrome (9156174716519).
The spelling of 2114042312407 in words is "two trillion, one hundred fourteen billion, forty-two million, three hundred twelve thousand, four hundred seven".
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